Module 04

Capacitors

Last Updated: Sun May 31 09:18:17 CDT 2020

Quiz

What is a Capacitor?

A capacitor stores charge

Questions?

Our Job

How they work…

\(Q = CV\)

This is the general definition of capacitance…

\(C = Q/V\)

The charge a capacitor can store, divided by the potential difference applied, is its capacitance.

Demo: Let’s charge some capacitors

NOTE about \(V\) and \(Q\) for capacitors

\(Q = CV\) actually means \(|Q_\text{one plate}| = C \Delta |V_\text{between plates}|\)

How much charge does this giant thing store?

Label says 89000 microfarad…

What is the capacitance of the Van de Graaff Generator?

The Van de Graaff generator had much less charge on it. That’s because it has a much smaller capacitance.

Recall: \(\approx 2.48\times 10^{-5}\text{C}\) for \(1.5\times 10^6 \text{V}\).

The capacitor contains plates…

The capacitor contains plates…

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Permittivity

\(\epsilon\) is called the “permittivity”

\(\epsilon_0\) is the “permittivity of free space”

\(\epsilon_0 = \frac{1}{4\pi k}\)

The permittivity of any material is greater than the permittivity of free space, and can be written as

\(\epsilon = \kappa \epsilon_0\)

where \(\kappa\) is the “dielectric constant”

Different materials have a different dielectric constants:

Field between the plates

In this class, we will always assume that the field between the two plates of a capacitor is uniform.

Let’s look at the field inside the capacitor

Remember, \(\Delta V = -\vec{E} \cdot \Delta \vec{r}\) (for uniform fields)

For parallel plate capacitor, \(\Delta V = \pm E d\)

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Hold voltage constant (with power supply) and make the plates smaller.

Hold voltage constant (with power supply) and make the plates smaller.

What happened?

So, \(C = \frac{Q}{V}\) must go down.

OK, so if I make the plates smaller, the capacitance goes down. That makes sense.

Hold voltage constant (with power supply) and bring plates closer together.

Hold voltage constant (with power supply) and bring plates closer together.

What happened?

So, \(C = \frac{Q}{V}\) must go up.

What does the dielectric do?

Remove capacitor from voltage source and put a dielectric material inside.

Remove capacitor from voltage source and put a dielectric material inside.

Remove capacitor from voltage source and put a dielectric material inside.

What happened?

So, \(C = \frac{Q}{V}\) must go up.

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OK, so there are 3 ways to change the capacitance of a parallel plate capacitor.

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How much work does it take to charge the capacitor?

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Consider a simple parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance \(d\). Suppose the plates are pulled apart while the charge on the capacitor remains constant, until they are separated by a distance \(D > d\). What will happen to the potential difference between the plates of the capacitor.

A. it will increase

B. it will decrease

C. it remain the same

Consider a simple parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance \(d\). Suppose the plates are pulled apart while the charge on the capacitor remains constant, until they are separated by a distance \(D > d\). What will happen to the energy stored in the capacitor?

A. it will increase

B. it will decrease

C. it remain the same

Consider a simple parallel-plate capacitor whose plates are given equal and opposite charges and are separated by a distance \(d\). Suppose the plates are pulled apart while the potential difference across the capacitor remains constant, until they are separated by a distance \(D > d\). What will happen to the energy stored in the capacitor?

A. it will increase

B. it will decrease

C. it remain the same

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Effective Capacitance

Different textbooks use different terms for capacitance of a group of capacitors.

These mean the same thing.

Let’s charge these two capacitors…

What is the potential difference across the capacitors?

Parallel/Series Combinations

Consider the circuit below.

Whiteboards

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Examples

Determine:

\(C_{eff} = \frac{20}{9} \text{F}\)

6 F 3 F 2 F 12 F
Q 100/9 C 60/9 C 40/9 C 100/9 C
V 50/27 V 60/27 V 60/27 V 25/27 V

Assume that all capacitors are parallel plate capacitors, filled with air, with identical plates. If the voltage of the emf were slowly increased, which capacitor would reach its breakdown limit first?

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Examples

Consider the following experiment:

What will the potential difference between the capacitor terminals be?

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Last Slide